Delphi/Lazarus: Get File Name of own Application

You can read out the EXE file of your own application by using Paramstr(0) as a well as with Application.ExeName.

However, both also provide you additionally with the complete application path, so that you have to divide path and program name from each other:

var
  MyEXE: string;
begin

  MyEXE := ExtractFileName(Application.ExeName);

  // or

  MyEXE := ExtractFileName(Paramstr(0));

end;

With ExtractFileName(), you can cut off the path from your program file so that you will only get the name of your EXE.
Last update on 2024-01-12 | Created on 2016-06-07