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Delphi/Lazarus: Get Name of own Application

Question by Compi | 06/06/2016 at 16:09

Is there any possibility to determine or retrieve the name of the EXE file of the own program? For example "MyProgram.exe" or whatever the name is?

Of course, theoretically, I know how I have named my own EXE, but, however, the user could have named the program file to any other arbitrary name. And this is the case I would like to check for.



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You can read out the EXE file of your own application by using Paramstr(0) as a well as Application.ExeName.

However, both ways are additionally providing the complete application path, so that you have to divide path and program name from each other:

  MyEXE: string;

  MyEXE := ExtractFileName(Application.ExeName);

  // or

  MyEXE := ExtractFileName(Paramstr(0));


With ExtractFileName(), you can cut off the path from your program file so that you will get the name of your EXE.
07/06/2016 at 11:24

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