Java: Integer from String or default Integer as Result

Of course, you can quickly write such a function on your own. It can look like the following (the first parameter is the string, the second parameter is the default integer):

public static int parseIntOrDefault(String value, int defaultValue) {
  int result = defaultValue;
  string s = StringUtils.trim(value);
  try {
    result = Integer.parseInt(s);
  } catch (Exception e) { }
  return result;
}

Calling the function can be done like that:

int i = parseIntOrDefault("123", 0));   // 123
int i = parseIntOrDefault("ABC", 0));   // 0
int i = parseIntOrDefault(" 1 ", 0));   // 1

The first line in this example converts the string "123" to the number 123. In the second line, we are passing the string "ABC" so that we get the specified default value 0 as a result.

By the way, we are using the line StringUtils.trim(value) in our function. With this, we are cutting off possible whitespace from the beginning and the end of the string before converting. The third line in our example is demonstrating that.
2016-08-05 at 22:07